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jq中$.getJSON用法
- jquery
- 2018-07-10
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简介json_encode() 对数组进行json转换 json_decode() 对json进行数组转换 <?php $array_1['username'] = "ericwolf"; $array_1['age'] = 25;
json_encode() 对数组进行json转换
json_decode() 对json进行数组转换
<?php $array_1['username'] = "ericwolf"; $array_1['age'] = 25; echo json_encode($member); ?>
<html> <head> <title>TODO supply a title</title> <meta charset="UTF-8"> <meta name="viewport" content="width=device-width"> <script type="text/javascript" src="jquery-1.9.1.min.js"></script> </head> <body> <script type="text/javascript"> $("document").ready(function() { var url ="client_2.php"; var data={}; $.getJSON(url,data,function(res){ $("#username").val(res.username); $("#address").val(res.age); }); }); </script> Username:<input type="text" name="username" id="username" /> Address:<input type="text" name="address" id="address" /> </body> </html>
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